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āĻāĻ–āύ āύāĻŋāĻœā§‡āχ āĻ•āĻŽā§āĻĒāĻŋāωāϟāĻžāϰ āĻāϰ āϏāĻ•āϞ āĻ•āĻžāϜ āύāĻŋā§Ÿā§‡ āύāĻŋāĻœā§‡āχ āĻ•āĻžāϜ āĻ•āϰ⧁āύ āĻāĻŦāĻ‚ āĻšāĻžāϜāĻžāϰ āϟāĻžāĻ•āĻž āĻŦāĻžāϚāĻžāύāĨ¤āφāĻŽāĻžāĻĻ⧇āϰ āĻĢāĻžāχāϞāϗ⧁āϞ⧋ āĻĢ⧁āϞ āχāĻĄāĻŋāĻŸā§‡āĻŦāϞ āύāĻŋāĻœā§‡ āύāĻŋāĻœā§‡āχ āĻ•āĻžāϜ āĻ•āϰāϤ⧇ ...
06/11/2022

āĻāĻ–āύ āύāĻŋāĻœā§‡āχ āĻ•āĻŽā§āĻĒāĻŋāωāϟāĻžāϰ āĻāϰ āϏāĻ•āϞ āĻ•āĻžāϜ āύāĻŋā§Ÿā§‡ āύāĻŋāĻœā§‡āχ āĻ•āĻžāϜ āĻ•āϰ⧁āύ āĻāĻŦāĻ‚ āĻšāĻžāϜāĻžāϰ āϟāĻžāĻ•āĻž āĻŦāĻžāϚāĻžāύāĨ¤
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āĻŽā§‚āĻ˛ā§āϝāσ 100 āϟāĻžāĻ•āĻž
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(āχāύāϏāĻžāφāĻ˛ā§āϞāĻžāĻš)
āύāĻŋāϤ⧇ āϚāĻžāχāϞ⧇ āĻŽāĻžāϏ⧇āϜ āĻ•āϰ⧁āύ.....

āĻāĻ•āĻŽāĻžāĻ¤ā§āϰ āĻŦāĻ‡ā§Ÿā§‡āϰ āĻŽāĻžāĻ§ā§āϝāĻŽā§‡ āĻĒā§āϰāĻ•ā§ƒāϤ āϏāĻ¤ā§āϝ āϜāĻžāύāĻž āϝāĻžā§ŸāĨ¤ āĻœā§āĻžāĻžāύ⧇āϰ āĻĒāϰāĻŋāϧāĻŋ āĻŦāχ āĻĒā§œā§‡ āĻŦāĻžā§œā§‡āĨ¤ āϤāĻžāχ āĻŽāĻžāĻ¤ā§āϰ ā§Ģā§Ļ/- āϟāĻžāĻ•āĻžā§Ÿ ā§Žā§¨ā§§āϟāĻŋ pdf āĻŦāχ āĻĒāĻžāĻŦ⧇āĨ¤ āϝāĻž āĻ•āĻŋāύāϤ⧇ ...
02/11/2022

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1.. (a+b)²= a²+2ab+b²2.. (a+b)²= (a-b)²+4ab3.. (a-b)²= a²-2ab+b²4.. (a-b)²= (a+b)²-4ab5.. a² + b²= (a+b)²-2ab.6.. a² + b...
18/07/2022

1.. (a+b)²= a²+2ab+b²
2.. (a+b)²= (a-b)²+4ab
3.. (a-b)²= a²-2ab+b²
4.. (a-b)²= (a+b)²-4ab
5.. a² + b²= (a+b)²-2ab.
6.. a² + b²= (a-b)²+2ab.
7.. a²-b²= (a +b)(a -b)
8.. 2(a²+b²)= (a+b)²+(a-b)²
9.. 4ab = (a+b)²-(a-b)²
10.. ab = {(a+b)/2}²-{(a-b)/2}²
11.. (a+b+c)² = a²+b²+c²+2(ab+bc+ca)
12.. (a+b)Âŗ = aÂŗ+3a²b+3ab²+bÂŗ
13.. (a+b)Âŗ = aÂŗ+bÂŗ+3ab(a+b)
14.. (a-b)Âŗ= aÂŗ-3a²b+3ab²-bÂŗ
15.. (a-b)Âŗ= aÂŗ-bÂŗ-3ab(a-b)
16.. aÂŗ+bÂŗ= (a+b) (a²-ab+b²)
17.. aÂŗ+bÂŗ= (a+b)Âŗ-3ab(a+b)
18.. aÂŗ-bÂŗ = (a-b) (a²+ab+b²)
19.. aÂŗ-bÂŗ = (a-b)Âŗ+3ab(a-b)
20.. (a² + b² + c²) = (a + b + c)² – 2(ab + bc + ca)
21.. 2 (ab + bc + ca) = (a + b + c)² – (a² + b² + c²)
22.. (a + b + c)Âŗ = aÂŗ + bÂŗ + cÂŗ + 3 (a + b) (b + c) (c + a)
23.. aÂŗ + bÂŗ + cÂŗ – 3abc =(a+b+c)(a² + b²+ c²–ab–bc– ca)
24.. a3 + b3 + c3 – 3abc =ÂŊ (a+b+c) { (a–b)²+(b–c)²+(c–a)²}
25.. (x + a) (x + b) = x² + (a + b) x + ab
26.. (x + a) (x – b) = x² + (a – b) x – ab
27.. (x – a) (x + b) = x² + (b – a) x – ab
28.. (x – a) (x – b) = x² – (a + b) x + ab
29.. (x+p) (x+q) (x+r) = xÂŗ + (p+q+r) x² + (pq+qr+rp) x +pqr
30.. bc (b-c) + ca (c- a) + ab (a - b) = - (b - c) (c- a) (a - b)
31.. a² (b- c) + b² (c- a) + c² (a - b) = -(b-c) (c-a) (a - b)
32.. a (b² - c²) + b (c² - a²) + c (a² - b²) = (b - c) (c- a) (a - b)
33.. aÂŗ (b - c) + bÂŗ (c-a) +cÂŗ (a -b) =- (b-c) (c-a) (a - b)(a + b + c)
34.. b²-c² (b²-c²) + c²a²(c²-a²)+a²b²(a²-b²)=-(b-c) (c-a) (a-b) (b+c) (c+a) (a+b)
35.. (ab + bc+ca) (a+b+c) - abc = (a + b)(b + c) (c+a)
36.. (b + c)(c + a)(a + b) + abc = (a + b +c) (ab + bc + ca)
37. đŸ”ŖāφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āĻ°đŸ”Ŗ
38. 1.āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ = (āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ × āĻĒā§āϰāĻ¸ā§āĻĨ) āĻŦāĻ°ā§āĻ— āĻāĻ•āĻ•
39. 2.āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻĒāϰāĻŋāϏ⧀āĻŽāĻž = 2 (āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ+āĻĒā§āϰāĻ¸ā§āĻĨ)āĻāĻ•āĻ•
40. 3.āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻ•āĻ°ā§āĻŖ = √(āĻĻ⧈āĻ°ā§āĻ˜ā§āĻ¯Â˛+āĻĒā§āϰāĻ¸ā§āĻĨ²)āĻāĻ•āĻ•
41. 4.āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ= āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāĻ˛ÃˇāĻĒā§āϰāĻ¸ā§āϤ āĻāĻ•āĻ•
42. 5.āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻĒā§āϰāĻ¸ā§āϤ= āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāĻ˛ÃˇāĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āĻāĻ•āĻ•
43.đŸ”ŖāĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āĻ°đŸ”Ŗ
44. 1.āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ = (āϝ⧇ āϕ⧋āύ āĻāĻ•āϟāĻŋ āĻŦāĻžāĻšā§āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ)² āĻŦāĻ°ā§āĻ— āĻāĻ•āĻ•
45. 2.āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻĒāϰāĻŋāϏ⧀āĻŽāĻž = 4 × āĻāĻ• āĻŦāĻžāĻšā§āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āĻāĻ•āĻ•
46. 3.āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻ•āĻ°ā§āĻŖ=√2 × āĻāĻ• āĻŦāĻžāĻšā§āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āĻāĻ•āĻ•
47. 4.āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ

28/06/2022

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